HOW MANY OAKLEYS DO U HAVE IN YOUR ARSENAL?

[Lavarock]

7 pairs and counting. Mostly metals. R1, 2-Juliets, 2-Pennys, Straight Jacket, and a Radar Path. Pit Boss 2 and R2 are up next.

 

[Rustpot]

Does that count all the different M-frame lens combos you can put together?

Oh golly.

Let's settle on 44 pairs, 17 or so of them are M Frame... frames. M Frame lenses are numbering at about 40 themselves.

(44-17) + (17x40) = 707

But I've got 2 Radarlocks, each with a lens, so add another 2 possibilities = 709

Tens I have 4? pairs of (let's think, black/fire, multicam, black/VR28BIP, brown smoke) yes, 4. But 3 being custom you've got another (3x3-3) 6 combos = 715

Everything else I keep stock colorways or I don't have lenses to swap.

So potentially I've got over 700 frame/lens combos sitting in my two towers. And my glove box. And my desk at work. And my briefcase. And probably somewhere else. Assuming I counted right, and not accounting for rubber color variations.

 

[qtrain23]

Oh golly.

Let's settle on 44 pairs, 17 or so of them are M Frame... frames. M Frame lenses are numbering at about 40 themselves.

(44-17) + (17x40) = 707

But I've got 2 Radarlocks, each with a lens, so add another 2 possibilities = 709

Tens I have 4? pairs of (let's think, black/fire, multicam, black/VR28BIP, brown smoke) yes, 4. But 3 being custom you've got another (3x3-3) 6 combos = 715

Everything else I keep stock colorways or I don't have lenses to swap.

So potentially I've got over 700 frame/lens combos sitting in my two towers. And my glove box. And my desk at work. And my briefcase. And probably somewhere else. Assuming I counted right, and not accounting for rubber color variations.

Isn't it not really 17x40 but a factorial?

Or a power rather. 17^40?

 

[OakleyFrankFMJ]

Isn't it not really 17x40 but a factorial?

Hmmmmm.....I think you are correct....that would bring the numbers significantly higher too.

 

[qtrain23]

Hmmmmm.....I think you are correct....that would bring the numbers significantly higher too.

Yea. 17! Is 355.65 trillion.

But i think it'd actually be 40 lenses with 17 frame combinations, so 40^17, or 1717986918400000000000000000
, allowing repetition.

 

[Rustpot]

No, the number of combinations is 17 frames with a choice of 40 lenses. 1 frame 40 choices, 2nd frame 39 choices. So 17 x 40.

The number of distinct combinations that can be made as a set number is a much larger number, meaning my collection can be presented at any one time as any one of N combinations. N is quite large.

But I can only make ~700 distinct pairs of sunglasses.

 

[kronin323]

No, the number of combinations is 17 frames with a choice of 40 lenses. 1 frame 40 choices, 2nd frame 39 choices. So 17 x 40.

The number of distinct combinations that can be made as a set number is a much larger number, meaning my collection can be presented at any one time as any one of N combinations. N is quite large.

But I can only make ~700 distinct pairs of sunglasses.

Even with that it'd take about two years to get through them all, wearing a different one each day with no repetitions. That's a lot of distinct posts to the "what are you wearing today" thread, you'd end up the member with the most likes on the forum, maybe...

 

[ThePitBoss]

Still updating every year. Will update on July 16 again

7-16-12 11 pairs
7-16-13 41 pairs
3-20-14 58 pairs

Lol I actually started 3 months after you but I have 54 Lol we need to go to Oakleys Anonymous KIK! Keep up the great work Bro!

 

[pjd1234]

my goodness when I started here in the forum jan14 I think ive owned 15 xmetals 3 xmetal xx and 11 juliets 1 mars after 2 months that doubled I decided to join because I wanted to get this Juliet fixed but no hope

this incident triggered the addiction for me to xmetals again a blessing in disguise I guess

 

[ThePitBoss]

man I envy you with that many xmetals man lol im gonna try and get X's soon but yea u r da mna lol